Sort an Array of Objects by Property Using sort(fn)

Discussion

1. Boger

   Nice read, never thought to sort objects this way. but man broseph and brochacho got me laugh to death :D
2. champi

   Great ! how could I do this in PHP ?
3. Jonathan Petitcolas

   A little bit late, but it still may be useful… ;)

   In PHP, it is almost the same. Here is the equivalent code:

   $people = array(
     array('name' => 'Robin Van Persie', 'age' => 28),
     array('name' => 'Theo Walcott', 'age' => 22),
     array('name' => 'Bacary Sagna', 'age' => 26)
   );
   
   usort($people, function($a, $b) {
     return $a['age'] - $b['age'];
   });
   
   var_dump($people);
   

   More informations: http://php.net/manual/fr/function.usort.php
4. Anil Gautam

   Hey I am tring your code but its not working.
5. mauro

   hi, i have tryed to bud a sort function by attributes a lot really, and finally i find this blog, your code work for me if the attribute is a number not if it is a string, why? i have to do something in that case? really thank you
6. Do Jo

   What if I wanted to sort by “name”?
• hlper

  http://stackoverflow.com/questions/10198257/comparing-2-strings-alphabetically-for-sorting-purposes
7. Fahad Rafiq

   Array sorting is very important when we deal with many array elements. We have variety of array functions which can sort arrays with respect to value as well as with respect to key. Explore the most important array sorting functions in PHP here: http://www.cloudways.com/blog/php-arrays-sorting-functions/.
8. George

   Why do you do

   return obj1.age - obj2.age;

   and not

   return obj1.age > obj2.age;

   .. and most importantly why do these two things give the same result?:)
9. Lumberjack

   Sorry but it seems the parser screwed up my message. Let me try again:

   return a.age - b.age;

   The above will return -1 if a is less than b.
   If a is equal to b, then it will return 0.
   If a is greater than b, then it will return 1.

   return a.age > b.age;

   This however will return a binary.
   If a is greater than b, then it will return true.
   In all other cases where a is equal to b OR a is less than b, it will return false.

   This will give an incorrect result for the case where a is less than b.

   Hopefully that makes sense.
10. Jay

    Hi When I sort the below array of objects by its x.

    [ { x: 0, s: '-' },
      { x: 6, s: '-' },
      { x: 0, s: '-' },
      { x: 6, s: '-' },
      { x: 4, s: '-' },
      { x: 0, s: '-' },
      { x: 6, s: '-' },
      { x: 0, s: '-' },
      { x: 6, s: '-' },
      { x: 0, s: '-' },
      { x: 4, s: 'that' },
      { x: 3, s: 'be' },
      { x: 0, s: 'to' },
      { x: 1, s: 'be' },
      { x: 5, s: 'question' },
      { x: 1, s: 'or' },
      { x: 2, s: 'not' },
      { x: 4, s: 'is' },
      { x: 2, s: 'to' },
      { x: 4, s: 'the' } ]
    
    this is what I get
    
    [ { x: 0, s: '-' },
      { x: 0, s: 'to' },
      { x: 0, s: '-' },
      { x: 0, s: '-' },
      { x: 0, s: '-' },
      { x: 0, s: '-' },
      { x: 1, s: 'be' },
      { x: 1, s: 'or' },
      { x: 2, s: 'to' },
      { x: 2, s: 'not' },
      { x: 3, s: 'be' },
      { x: 4, s: 'the' },
      { x: 4, s: 'is' },
      { x: 4, s: '-' },
      { x: 4, s: 'that' },
      { x: 5, s: 'question' },
      { x: 6, s: '-' },
      { x: 6, s: '-' },
      { x: 6, s: '-' },
      { x: 6, s: '-' } ]
    

    If you check its getting sorted in ascending order but its changing my input order, if you see the object at index[1] should have been placed at index[5] on basis how the array input is so can any one let me know how do we achieve that.

    This is my code

    m = m.sort(function(a,b){return a.x - b.x});
       console.log(m);
11. Eddie Ebeling

    Good stuff, brah! Saved me 5 more Google searches!
12. Peter T

    Here is one that is pretty funky, it sorts by time, when time is a string:

    newAddEvents.sort((a, b) => (Date.parse('1970-01-01T' + a.time) > Date.parse('1970-01-01T' + b.time)) ? 1 : -1);