Checking For Leap Year Using PHP

By  on  

One part of programming that seems pretty static is dealing with dates. The calendar is a set system of rules that doesn't look to change. The only part of the calendar that can be variable is a leap year, which changes every four years (obviously).

Using pure PHP ternary logic, much like the PHP Function - Calculating Days In A Month, I posted a few weeks back, you can check to see if a year is a leap year.

The Code

function is_leap_year($year) {
	return ((($year % 4) == 0) && ((($year % 100) != 0) || (($year % 400) == 0)));
}

Recent Features

  • By
    5 HTML5 APIs You Didn’t Know Existed

    When you say or read "HTML5", you half expect exotic dancers and unicorns to walk into the room to the tune of "I'm Sexy and I Know It."  Can you blame us though?  We watched the fundamental APIs stagnate for so long that a basic feature...

  • By
    Interview with a Pornhub Web Developer

    Regardless of your stance on pornography, it would be impossible to deny the massive impact the adult website industry has had on pushing the web forward. From pushing the browser's video limits to pushing ads through WebSocket so ad blockers don't detect them, you have...

Incredible Demos

  • By
    Scrolling “Go To Top” Link Using Dojo

    One of the most popular code snippets of posted on my blog has been the scrolling "Go To Top" link snippet. The premise of the snippet is simple: once the user scrolls an element (usually the BODY element) past a given threshold, a "Go...

  • By
    Detect Vendor Prefix with JavaScript

    Regardless of our position on vendor prefixes, we have to live with them and occasionally use them to make things work.  These prefixes can be used in two formats:  the CSS format (-moz-, as in -moz-element) and the JS format (navigator.mozApps).  The awesome X-Tag project has...

Discussion

  1. Placing a function call as an argument default will result in a fatal error. Also, give this version a shot:

    function is_leap_year( $year = NULL )
    {
        if_numeric( $year ) || $year = date( 'Y' );
        return checkdate( 2, 29, ( int ) $year );
    }
  2. Whoops, small typo… if_numeric( $year ) should be is_numeric( $year )… :x

  3. Tamlyn

    Better yet, use date('L') which returns 1 if it’s a leap year, 0 if it isn’t.

  4. I do agree with tamlyn, why you dont use date function??
    It can makes a load fasting right?

  5. Travis

    date(‘L’) is way better because leap year is not every 4 years.

  6. Date("L") only tell you in a given year, default is the year today.
    If you need to know whether previous or next year is a leap, you must reset the date.
    It could affect the system.

    • Indra, you can always pass the timestamp as second parameter to date function:

      echo date('L', mktime(1, 1, 1, 1, 1, 2005));
      
  7. I think this is a better example relating to the function. Also provided example for anyone looking for true/false as I was in this instance.

    /* for true or false */
    function is_leap_year($year)
    {
    	return ( date ('L', mktime(1,1,1,1,1, $year) ) === 1 ) ? true : false;
    }
    /*for 0 or 1 Whether it's a leap year: 1 if it is a leap year, 0 otherwise. */
    function is_leap_year($year)
    {
    	return date ('L', mktime(1,1,1,1,1, $year) );		
    }
    
  8. Habibur Rahaman
    <?php
    $day = "";
    for($i=0; $i<4; $i++)
    {
        $day =  date("d", mktime(0, 0, 0, 2, 29, date("Y")+$i));
        if($day == 29)
        {
            $year = date("Y")+$i;
            break;
        }
    }
    echo "The next leap year is 29th February $year";    
    ?>
    
    
  9. Milan Dvořák

    code of Habibur Rahaman will not work for example for the year 1897, because 1900 is not leap year.

Wrap your code in <pre class="{language}"></pre> tags, link to a GitHub gist, JSFiddle fiddle, or CodePen pen to embed!